Continuity and Differentiability

Bihar Board Class 12 · Mathematics · 139 past questions

9 of 139 · show all

1. Q13 2026 Set A2026 Set H2026 Set E2026 Set C2026 Set F2026 Set D2026 Set J2026 Set B

   $\frac{d}{dx}\sin^{-1}(3x - 4x^3) =$

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2. Q34 2025

   $\dfrac{d\cos^{-1}(\sin x)}{dx} =$

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3. Q59 2025 Set A2025 Set E

   $\dfrac{d}{dx}\left[\sin^{-1}\left(2x\sqrt{1-x^2}\right)\right] =$

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4. Q68 2024 Set D2024 Set J

   If $y=\tan^{-1}\left(\dfrac{1-\cos x}{\sin x}\right)$ then $\dfrac{dy}{dx}=$

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5. Q97 2021 Set I

   $\frac{d}{dx}\{\sin^{-1}(3x-4x^3)\}$ ; ................ $-\frac{1}{2}\le x\le\frac{1}{2}$

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6. Q106 2021 Set J

   $\dfrac{d}{dx}\{\sin^{-1}(3x-4x^3)\}=\ldots\ldots,\ -\frac{1}{2}\le x\le\frac{1}{2}$

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7. Q121 2018

   $\frac{d}{dx}\left[\tan^{-1}\sqrt{1+x^2} - \cot^{-1}\left(-\sqrt{1+x^2}\right)\right] =$

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8. Q122 2018

   $\frac{d(2^x)}{d(3^x)} =$

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9. Q126 2018

   If $y = \tan^{-1}\left(\dfrac{\cos x}{1+\sin x}\right)$ then find $\dfrac{dy}{dx}$.

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